BaaaaaaaarkingDog
코딩, 해킹
[Cryptanalysis] Pixel Madness

 

대체 무엇을 하라는건가 모르겠어서 풀이를 보고 이해했습니다.(https://tgraph.io/CTF-Kurs-molodogo-bojca-Nachalnye-zadaniya-kategorii-Crypto-3-09-25 현재는 삭제된 글..ㅠ)

I really cannot understand what this problem is asking about, so I learned it by solution.(https://tgraph.io/CTF-Kurs-molodogo-bojca-Nachalnye-zadaniya-kategorii-Crypto-3-09-25 deletedㅜㅜ)

 

게싱 싫어욧

I don't like guessing :(

from Crypto.Util.number import *
import binascii,socket,sys

def gcd(a, b):
  if a == 0: return b
  return gcd(b%a, a)

def egcd(a, b):
  if a == 0:
    return (b, 0, 1)
  g, y, x = egcd(b%a,a)
  return (g, x - (b//a) * y, y)

def inv(a, m):
  g, x, y = egcd(a, m)
  if g != 1:
    raise Exception('No modular inverse')
  return x%m

# x**2 = a (mod m), m is prime
def quad_congruence_equation(a, m):
  assert((m+1)%4 == 0)
  return pow(a, (m+1)//4, m)
# m must satisfies pairwise relatively prime
def crt(a, m):
  n = len(m)
  ret = a[0]
  mod = m[0]
  for i in range(1,n):
    m1 = mod
    mod *= m[i]
    m2inv = inv(m[i],m1)
    m1inv = inv(m1,m[i])
    ret = (ret*m[i]*m2inv+a[i]*m1*m1inv)%mod
  return ret

# 0x6161 -> 'AA'
def i2s(x):
  return long_to_bytes(x).decode("utf-8")

############ my socket ###############
def interactive(socket):
  print("[+] interactive mode")
  while True:
    rr = socket.recv(2**16).decode()
    if not rr:
      print("[!] socket closed")
      return None
    print(rr)
    socket.send((input('> ')+'\n').encode())

def remote(ip, port):
  sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
  print("[+] Connecting to {}:{}".format(ip,port))
  sock.connect((ip,port))
  print("[+] Done!")
  return sock

def sendline(socket, msg):
  if type(msg) == str: msg = msg.encode()
  if msg[-1] != b'\n': msg += b'\n'
  socket.send(msg)

###################################

S='''0x3+1x1+0x1+0x1+0x7+1x2+0x15+1x1+0x8+1x1+0x8+1x1+0x1+1x1+0x1+1x1+0x1+1x1+0x1+1x1+0x3+1x1+0x1+1x1+0x3+1x1+0x1+1x4+0x2+1x1+0x25
0x2+1x1+0x4+1x1+0x4+1x3+0x1+1x2+0x2+1x8+0x11+1x4+0x1+1x3+0x6+1x2+0x4+1x1+0x4+1x2+0x7+1x4+0x4+1x2+0x7+1x2+0x3+1x2+0x3
0x3+1x1+0x2+1x1+0x2+1x1+0x11+1x2+0x2+1x3+0x7+1x1+0x4+1x2+0x2+1x2+0x7+1x1+0x6+1x1+0x2+1x1+0x4+1x3+0x1+1x1+0x4+1x1+0x2+1x1+0x2+1x1+0x3+1x1+0x2+1x3+0x2+1x2+0x3
1x1+0x2+1x1+0x4+1x1+0x2+1x1+0x1+1x1+0x2+1x1+0x2+1x1+0x1+1x2+0x2+1x2+0x1+1x2+0x3+1x1+0x3+1x1+0x2+1x2+0x1+1x3+0x3+1x1+0x2+1x1+0x4+1x2+0x1+1x1+0x4+1x1+0x3+1x2+0x12+1x2+0x1+1x1+0x3+1x7+0x3
0x3+1x1+0x7+1x1+0x1+1x1+0x4+1x1+0x2+1x2+0x2+1x2+0x4+1x1+0x2+1x1+0x1+1x2+0x1+1x8+0x1+1x1+0x4+1x1+0x5+1x1+0x3+1x2+0x2+1x1+0x1+1x2+0x2+1x1+0x3+1x2+0x9+1x1+0x1+1x2+0x2+1x3+0x2+1x1                
0x7+1x1+0x4+1x1+0x4+1x1+0x1+1x1+0x1+1x7+0x3+1x1+0x1+1x2+0x3+1x1+0x1+1x6+0x1+1x1+0x3+1x1+0x2+1x1+0x14+1x2+0x8+1x1+0x10+1x2+0x3+1x2+0x1+1x1+0x1
0x6+1x5+0x4+1x1+0x7+1x1+0x2+1x1+0x3+1x2+0x4+1x1+0x8+1x1+0x3+1x2+0x1+1x2+0x3+1x1+0x8+1x1+0x2+1x2+0x1+1x1+0x3+1x7+0x5+1x2+0x2+1x1+0x2+1x2+0x3
0x1+1x1+0x2+1x1+0x1+1x2+0x5+1x1+0x6+1x2+0x3+1x1+0x2+1x1+0x1+1x2+0x20+1x8+0x1+1x1+0x1+1x1+0x4+1x2+0x3+1x1+0x2+1x2+0x3+1x2+0x7+1x2+0x3+1x2+0x4
0x2+1x1+0x3+1x5+0x5+1x2+0x7+1x1+0x4+1x2+0x2+1x1+0x2+1x2+0x1+1x1+0x3+1x1+0x6+1x2+0x2+1x2+0x3+1x2+0x2+1x3+0x1+1x1+0x6+1x3+0x3+1x5+0x3+1x1+0x4+1x1+0x5
0x4+1x2+0x3+1x2+0x3+1x1+0x5+1x2+0x2+1x1+0x1+1x1+0x1+1x1+0x1+1x2+0x9+1x1+0x3+1x1+0x2+1x1+0x1+1x1+0x2+1x1+0x1+1x2+0x2+1x1+0x2+1x1+0x1+1x1+0x4+1x3+0x1+1x1+0x2+1x2+0x3+1x2+0x3+1x1+0x5+1x1+0x4+1x1+0x2
0x6+1x5+0x4+1x1+0x1+1x1+0x2+1x2+0x6+1x1+0x1+1x7+0x4+1x3+0x3+1x1+0x4+1x1+0x2+1x2+0x4+1x1+0x6+1x1+0x6+1x8+0x3+1x1+0x5+1x1+0x7
0x2+1x1+0x3+1x6+0x4+1x1+0x1+1x3+0x4+1x1+0x2+1x2+0x4+1x1+0x5+1x1+0x2+1x1+0x3+1x2+0x3+1x1+0x2+1x3+0x1+1x1+0x2+1x2+0x3+1x3+0x2+1x3+0x9+1x1+0x4+1x2+0x7+1x2'''.split()
sq = ['.', '#']
ans=''
for s in S:
  t = s.split('+')
  for c in t:
    if c[0] == '0': ans += sq[0]*int(c[2:])
    else: ans += sq[1]*int(c[2:])
  ans += '\n'
print(ans)

출력 결과를 보고 사륜안을 발동해서 적혀있는 글씨를 읽어내야합니다.

You should open your third eye and read the flag on output. Check it.

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